1
A sells a scooter priced at $3600. He gives a discount of 8% on the first $2000 and 5% on the next $1000. How much discount can be afforded on the remaining $600 if he is to get as much as when 7% discount is allowed on the total?
Answer & Solution
Solution:

Let, discount on $600 be x%.

Then, (100 – x)% of 600 = 93% of 3600 – (92% of 2000 + 95% of 1000)

    Or, 6(100 – x) = 3348 – (1840 + 950)

    Or, 600 – 6x = 3348 – 2790 = 558

    Or, 6x = 42

    Or, x = 7.

 

 

2
An article is listed at $900 and two successive discounts of 8% and 8% are given on it. How much would the seller gain or lose, if he gives a single discount of 16%, instead of two discounts?
A.
B.
C.
D.
Answer & Solution
Solution:

Loss = $[(92% of 92% of 900) – (84% of 900)]

        = $[(0.92 × 0.92 × 900) – (0.84 × 900)]

        = $[761.76 – 756]

        = $5.76.

 

3
Jack bought a camera and paid 20% less than its original price. He sold it at 40% profit on the price he had paid. The percentage of profit earned by Jack on the original price was
Answer & Solution
Solution:

Let, original price of the camera be $100

Then discounted price = $80 & Profit $40%

\ Selling price = 140% of $80 = (140/100) × $80 = $112.

Hence, percentage of profit earned by Jack on the original price = (12/100) × 100 = 12%

 

4
On a $10,000 payment order, a person has choice between 3 successive discounts of 10%, 10% and 30%, and 3 successive discounts of 40%, 5% and 5%. By choosing the better one he can save
A.
B.
C.
D.
Answer & Solution
Solution:

Successive Discounts of 10%, 10%, and 30%:

Price after first discount = 10,000 − (10% × 10,000) = 10,000 − 1,000 = 9,000

Price after second discount = 9,000 − (10% × 9,000) = 9,000 – 900 = 8,100

Price after third discount = 8,100 − (30% × 8,100) = 8,100 − 2,430 = 5,670

Successive Discounts of 40%, 5%, and 5%:

Price after first discount = 10,000 − (40% × 10,000) = 10,000 − 4,000 = 6,000

Price after second discount = 6,000 − (5% × 6,000) = 6,000 – 300 = 5,700

Price after third discount = 5,700 − (5% × 5,700) = 5,700 – 285 = 5,415

Now, Option 1 Final Price = $5,670

Option 2 Final Price = $5,415

Better Option = Option 2

Savings by choosing the better option = $5,670 - $5,415 = $255

 

5
A retailer allows a trade discount of 20% and a cash discount of 6 1/4% on the market price of the products and gets a net profit of 20%, on the cost. By how much above the cost, should the products be labelled for sale?
Answer & Solution
Solution:

Let, C.P.= $100 & M.P.=$x.

Then selling price = $120

Now, 93 ¾% of 80% of x = 120

 Or, 475/4 × 1/100 × 80/100 × x = 120

 Or, 3x/4 = 120

 Or, 3x = 480

 Or, x = 160

\ Labelled price = M.P. – C.P. = (160 – 100)% = 60% above cost price.

 

6
A trader marked his goods at 20% above the cost price. He sold half the stock at the marked price, one quarter at a discount of 20% on the marked price and the rest at a discount of 40% on the marked price. His total gain is
A.
B.
C.
D.
Answer & Solution
Solution:

Let, C.P. of whole stock = $100

Then marked price of whole stock = $100 × 120% = $120,

                                   half stock = $60

                                   quarter(1/4) stock = $30

\ Total selling price = $[60 + (80% of 30) + (60% of 30)]

                                  = $[60 + 24 + 18]

                                  = $102

Hence, gain = (102 – 100)% = 2%.

 

7
The labelled price of a cupboard is $650. The shopkeeper sold it by giving 5% discount on the labelled price and earned a profit of 15%. What approximately is the cost price of the cupboard?
A.
B.
C.
D.
Answer & Solution
Solution:

S.P. = 95% of $650 = $617.5

Profit = 15%

\ C.P.= $617.5 × (100/115) = $536.95 » $537.

 

8
A shopkeeper sold blazer at $266 each after giving 5% discount on labelled price. Had he not given the discount, he would have earned a profit of 12% on the cost price. What was the cost price of each blazer?
A.
B.
C.
D.
Answer & Solution
Solution:

S.P. of a blazer = $266

Let, the labelled price of each blazer = $x

Then, 95% of x = $266

      Þ x = $266 × (100/95)

      Þ x = $280

\ Cost price of 1 blazer = S.P. × (100/112)

                                       = $280 × (100/112)

                                       = $250.

 

9
The marked price of a shirt and trousers are in the ratio 1: 2. The shopkeeper gives 40% discount on the shirt. If the total discount on the set of the shirt and trousers is trousers is 30%, the discount offered on the trousers is
Answer & Solution
Solution:

Let the marked price of the shirt is x and the marked price of the trousers is 2x.

Then discount on Shirt = 40% of x = 0.4x

Total marked price = x+2x = 3x

Total discount amount = 30% of 3x = 0.3 × 3x = 0.9x

Let the discount on trousers be y%.

Then, the discount amount on the trousers

               y% of 2x

            = (y/100) × 2x 

            = 2yx/100

            = 0.02yx

Since the total discount from both the shirt and trousers is 0.9x,

               0.4x + 0.02yx = 0.9x

        Or, 0.02yx = 0.9x − 0.4x

        Or, 0.02yx = 0.5x

        Or, 0.02y = 0.50

        Or, y = 0.50/0.02

        Or, y = 25

\ The discount on trousers is 25%.

 

10
A shopkeeper sells a badminton racket, whose marked price is $30, at a discount of 15% and gives a shuttle cock costing $1.50 free with each racket. Even then he makes a profit of 20%. His cost price per racket is
Answer & Solution
Solution:

Let, C.P.= $x.

Marked price = $30

S.P.= $[(30 × 85%) – 1.50]

       = $(25.5 – 1.50)

       = $24

Accordingly, 120% of x = 24

                 Þ120x = 2400

                 Þ x = $20.