1
The ratio between the present ages of A and B is 5 : 3 respectively. The ratio between A's age 4 years ago and B's age 4 years hence is 1: 1. What is the ratio between A's age 4 years hence and B's age 4 years ago?
A.
B.
C.
D.
Answer & Solution
Let the present age of A be 5x and the present
age of B be 3x.
Then, A's age 4 years ago was 5x−4.
B's age 4 years hence will be 3x+4.
According to question,
(3x+4)
: (5x−4) = 1 : 1
⟹ 5x−4 = 3x+4
⟹ 5x−3x = 4+4
⟹ 2x = 8
⟹ x = 4
Thus, A's present age is 5x = 5(4) = 20 years,
and B's present age is 3x = 3(4) = 12 years.
Again, A's age 4 years hence will be 20+4=24
years.
B's age 4 years ago was 12−4=8 years.
\ The ratio between A's age 4 years hence and
B's age 4 years ago is 8 : 24 = 1:3
2
If at the time of their marriage, the ratio of their ages was 5: 3, then how many years ago were they married?
A.
B.
C.
D.
Answer & Solution
Let the present age of the man be 4x and his
wife be 3x.
After 4 years, the man's age will be 4x+4 and
the wife's age will be 3x+4.
Then, (4x+4) : (3x+4) = 9 : 7
⟹ 7(4x+4) = 9(3x+4)
⟹ 28x+28 = 27x+36
⟹ 28x−27x = 36−28
⟹ x = 8
Therefore, the present age of the man is 4x = 4(8)
= 32 years, and the present age of the wife is 3x = 3(8) = 24 years.
Let y years ago they were married.
Then the man's age at the time of marriage was
32−y and the wife's age was 24−y.
So, (32−y) : (24−y) = 5 : 3
⟹ 3(32−y) = 5(24−y)
⟹ 96−3y = 120−5y
⟹ 5y−3y = 120−96
⟹ 2y = 24
⟹ y = 12
Hence, they were married 12 years ago.
3
A man is aged three times more than his son Ronit. After 8 years, he would be two and half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
A.
B.
C.
D.
Answer & Solution
Let, M = man's age & R = Ronit's age.
Then, M = 4R …….. (i)
M + 8 =
2.5(R + 8)……….. (ii)
Substituting (i) into (ii),
4R + 8 = 2.5R + 20
⟹ 1.5R = 12
⟹ R = 8
\ M = 4 × 8 = 32
After 16 years,
Man = 32 + 16 = 48
Ronit = 8 + 16 = 24
Hence Ronit’s age would be 48 / 24 = 2 times.
4
One year ago, Promila was four times as old as her daughter Sakahi. Six years hence, Promila's age will exceed her daughter's age by 9 years. The ratio of the present ages of Promila and her daughter is
A.
B.
C.
D.
Answer & Solution
Let P = Promila's current age & S = Sakahi's current
age.
Then, one year ago P – 1 = 4(S – 1)
⟹ P = 4S – 3
and six years later P
+ 6 = S + 6 + 9
⟹ P = S + 9
Equating P, 4S – 3 = S + 9
⟹ 3S = 12
⟹ S = 4
Substituting value of S,
P = 4 + 9 = 13
\ Ratio of their present ages P : S = 13 : 4.
5
Tanya's grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. 8 years ago, what was the ratio of Tanya's age to that of her grandfather?
A.
B.
C.
D.
Answer & Solution
Let Tanya's current age be T and her grandfather's
age be G.
16 years ago,
G −16 = 8(T−16)
⟹ G = 8T – 112 ……… (i)
8 years from
now,
G +
8 = 3(T + 8)
⟹ G = 3T + 16
Substituting value of G in equation (i)
8T−112 = 3T+16
5T = 128
T = 25.6
Similarly, G = 92.8
8 years ago, age of
Tanya = 25.6
– 8 = 17.6
Grandfather
= 92.8 – 8 = 84.8
\
Ratio of their ages = 47.6 : 84.8 = 11:53
6
The difference between the ages of two men is 10 years. 15 years ago, the elder one was twice as old as the younger one. The present age of the elder man is ages?
A.
B.
C.
D.
Answer & Solution
Let the present age of the elder
man & younger man be E & Y respectively.
Then, E – Y = 10
Þ y = E – 10
15 years ago
their ages
Elder man = E−15
Younger man = Y−15
According to question,
E−15 = 2(Y−15)
Þ E−15
= 2(E−10−15) [Since Y = E−10]
Þ E -
15 = 2E – 50
Þ E =
35
7
Three years ago, the ratio of the ages of Amisha and Nimisha was 8:9 respectively 3 years hence, the ratio of their ages will be 11:12 respectively. What is the present age of Amisha?
A.
B.
C.
D.
Answer & Solution
Let Amisha's age 3 years ago be 8x and Nimisha's age 3 years
ago be 9x.
Since this was 3 years ago, their present ages are
Amisha = 8x+3
Nimisha = 9x+3
Three years hence their ages
Amisha = (8x+3) + 3 = 8x+6
Nimisha = (9x+3) + 3 = 9x+6
According to question,
(8x+6) : (9x+6) =11:12
Þ12(8x+6) = 11(9x+6)
Þ96x + 72 = 99x + 66
Þ96x – 99x = 66 – 72
Þ3x = 6
Þx = 2
\ Amisha’s present age = 8x+3 = 8(2)+3 = 16+3 = 19.
8
If 10 years are subtracted from the present age of Mr. Roy and the remainder divided by 14, then you would get the present age of his grandson Sachin. If Sachin is 9 years younger to Saloni whose age in 14 years, then what is the 0present age of Mr. Roy?
A.
B.
C.
D.
Answer & Solution
Let Mr. Roy’s present age be R and Sachin’s present age be S.
Then, R – 10
= 14S ………. (i)
Again, Sachin is 9 years younger than Saloni, and Saloni’s
age is 14 years.
So, S = 14 –
9 = 5
Substituting S = 5 into the equation (i),
R−10=14 × 5
ÞR = 80.
9
6 years ago, the ratio of the ages of Kunal and Sagar was 6:5. Four years hence, the ratio of their ages will be 11:10. What is Sagar's age at present?
A.
B.
C.
D.
Answer & Solution
Let
Kunal's age 6 years ago be 6x and Sagar's age 6 years ago be 5x.
Since
this was 6 years ago, their present ages are:
Kunal = 6x+6
Sagar = 5x+6
After four years their ages are
Kunal
= (6x+6)+4=6x+10
Sagar
= (5x+6)+4=5x+10
According
to question,
(6x+10) : (5x+10) = 11:10
Þ
10(6x+10) = 11(5x + 10)
Þ
60x – 55x = 110 – 100
Þ
5x = 10
Þ
x = 2
\ Sagar's
present age = 5x+6=5(2)+6=10+6=16.
10
Snch's age is 1/6th of her father's age. Sneh's father's age will be twice of Vimal's age after 10 years. If Vimal's 8th birthday was celebrated 2 years ago, then what is Sneh's present age?
A.
B.
C.
D.
Answer & Solution
Let Sneh, her father & Vimal’s present age be S, F &
V.
Then, S = 1/6 F ………….. (i)
& F+10 = 2(V+10)
………… (ii)
Vimal's age 2 years ago was 8.
So, Vimal's present age is V = 8+2 = 10 years.
Substitute V=10 into equation (ii),
F +10 = 2(10+10)
Þ F+10 = 2(20)
Þ F+10 = 40
Þ F = 30
Now, substitute F=30 into equation (i),
S = 61(30)
Þ S = 5
Therefore, Sneh's present age is 5 years.
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